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16+9x-x^2=0
We add all the numbers together, and all the variables
-1x^2+9x+16=0
a = -1; b = 9; c = +16;
Δ = b2-4ac
Δ = 92-4·(-1)·16
Δ = 145
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{145}}{2*-1}=\frac{-9-\sqrt{145}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{145}}{2*-1}=\frac{-9+\sqrt{145}}{-2} $
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